Two-vertex-cut certificate (Fiedler's κ ≤ 2 bound) #
If deleting two vertices a ≠ b disconnects the graph into two nonempty parts
A and B (no A–B edges), then algConn G ≤ 2, unconditionally.
Test vector: x = |B|·𝟙_A − |A|·𝟙_B (zero on {a, b}). Then ∑ x = 0,
x ≠ 0, and the key pointwise estimate is that every ordered adjacent pair
contributes (x i − x j)² ≤ (x i)²·c j + c i·(x j)² where c is the indicator
of the cut {a, b}: within A or within B the difference vanishes, A–B
edges are excluded by the separation hypothesis, and an edge into the cut
contributes exactly |B|² (from the A side) or |A|² (from the B side) —
which is precisely (x·)² at the non-cut endpoint. Summing, the ordered
quadratic form is at most 2 · (∑ c) · (∑ x²) = 4 ∑ x², hence
xᵀ L x ≤ 2 ∑ x² and the universal test-vector certificate applies.
Two-vertex-cut certificate, general vertex type. If {a, b} separates
the nonempty sets A and B (which together with a, b cover all vertices,
are disjoint, and have no edges between them), then algConn G ≤ 2.
Two-vertex-cut certificate on Fin n (Fiedler's κ ≤ 2 bound):
deleting the two vertices a ≠ b disconnects G into the nonempty parts
A and B, hence algConn G ≤ 2, unconditionally.