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LeanPool.Ado.Algebra.Lie.LeviDecomposition.Solvable

Levi's theorem #

Let L be a finite-dimensional Lie algebra over a field of characteristic zero. Levi's theorem says that the solvable radical R of L has a complementary Lie subalgebra S, a Levi complement. Such an S is isomorphic to L ⧸ R, so it is semisimple, and L is the semidirect sum R ⋊ S for the adjoint action of S on R.

The theorem is proved more generally for a solvable ideal I whose quotient L ⧸ I has nondegenerate Killing form (LieIdeal.exists_lieSubalgebra_isCompl_of_isSolvable); the radical is such an ideal by Cartan's criterion. The general form is the one that admits an induction.

The argument #

Induct on the dimension of L. Let A be the last nonzero term of the derived series of I: an abelian ideal of L contained in I. If I = 0 there is nothing to prove. Otherwise A ≠ 0, so L ⧸ A has smaller dimension, and its solvable ideal I ⧸ A has quotient L ⧸ I; by induction it has a complement S₁. The preimage P of S₁ in L is a Lie subalgebra with I + P = L and I ∩ P = A. The abelian ideal A of P has quotient P ⧸ A ≃ L ⧸ I, so the abelian case (LieIdeal.exists_lieSubalgebra_isCompl_of_isLieAbelian) complements it inside P, and that complement is a complement of I in L (LieIdeal.isCompl_map_incl).

Main results #

References #

A Levi complement of a solvable ideal. Over a field of characteristic zero, a solvable ideal I of a finite-dimensional Lie algebra L whose quotient L ⧸ I has nondegenerate Killing form has a complementary Lie subalgebra.

theorem Ado.exists_leviComplement (K : Type u) [Field K] (L : Type v) [LieRing L] [LieAlgebra K L] [CharZero K] [FiniteDimensional K L] :

Levi's theorem. Over a field of characteristic zero, the solvable radical of a finite-dimensional Lie algebra has a complementary Lie subalgebra, a Levi complement.

The Levi decomposition. Over a field of characteristic zero, a finite-dimensional Lie algebra is the semidirect sum of its solvable radical and a semisimple Lie subalgebra acting on the radical by the adjoint action.