The Complete Local Domain T #
Construction of T = C[[x,y,z]]/(x^2 - yz) and the proof that T is an integral domain.
The ideal (x² - yz) in ℂ[[x,y,z]] where x = X 0, y = X 1, z = X 2.
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The substitution map ψ : ℂ[[x,y,z]] → ℂ[[u,v]] defined by x ↦ u·v, y ↦ u², z ↦ v².
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- ψMap 0 = MvPowerSeries.X 0 * MvPowerSeries.X 1
- ψMap 1 = MvPowerSeries.X 0 ^ 2
- ψMap 2 = MvPowerSeries.X 1 ^ 2
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Explicit quotient: given f, define q so that f = q * (X₀² - X₁X₂) when ψ(f)=0. q(n₀,n₁,n₂) = Σ_{k=0}^{min(n₁,n₂)} f(n₀+2+2k, n₁-k, n₂-k).
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Key coefficient relation: the sum Σ_{k=0}^{min(m₁,m₂)} f(m₀+2k, m₁-k, m₂-k) equals a coefficient of ψHom(f) at the monomial u^{m₀+2m₁} v^{m₀+2m₂}.
Key lemma: ψbar is injective. This is equivalent to ker ψHom = conjI.
Proof sketch: View ℂ[[x,y,z]] ≅ ℂ[[y,z]][[x]] via the ring equiv. Under this decomposition, every f can be written uniquely as q·(x²-yz) + (a + bx). If ψ(f) = 0 then ψ(a + bx) = a(u²,v²) + b(u²,v²)·uv = 0. The terms a(u²,v²) use only even-even degree monomials while b(u²,v²)·uv uses only odd-odd degree monomials, so both must be zero. Since g ↦ g(u²,v²) is injective, a = b = 0, hence f = q·(x²-yz) ∈ conjI.