The Lipschitz pieces of Besicovitch's graph are null #
A point of [0, 1] that avoids every grid of level N, N + 1, … on both sides lies in a
set of measure zero. Indeed, inside a level-M cell the survivors of the levels up to M form
an interval, and the level-M + 1 grid punches holes of total relative size 1 / ((M+1) (L+1))
into every interval, up to an error of a few holes per cell. The errors are summable while
∑ 1 / ((M + 1) (L + 1)) diverges, so the recursion of
LeanPool.Besicovitch.Example.Recursion forces
the surviving measure to zero.
Combined with ae_eventually_mem_avoid, every subset of [0, 1] on which g is Lipschitz is
Lebesgue-null.
A subset of [0, 1] has finite Lebesgue measure.
Holes around grid points #
A hole is measurable.
A hole has measure 2 * margin L m.
Distinct holes of the same level are disjoint.
The estimate on one interval #
Per-interval estimate. An order-connected subset S of [0, 1] loses the fraction
1 / (m (L + 1)) of its measure, up to an error of 4 * margin L m, when the level-m grid
is avoided: the holes around the level-m grid points inside S are disjoint, are removed,
and number at least volume S / cellLength m - 2.
Summing over the cells of the previous level #
[0, 1] is covered by the level-M cells with indices 0, …, cellIndex M 1.
There are at most 1 / cellLength M + 1 level-M cells meeting [0, 1].
Consecutive cell lengths: cellLength (M + 1) = cellLength M * (1/2) ^ (2 M + 1).
One level of the recursion. If S ⊆ [0, 1] meets every level-M cell in an
order-connected set, then avoiding the level-M + 1 grid removes the fraction
1 / ((M + 1) (L + 1)) of its measure, up to an error 4 * (1/2) ^ (M + 1).
The survivors of the first n levels #
The points of [0, 1] avoiding the grids of levels N + 1, …, N + n.
Equations
- LeanPool.Besicovitch.Example.survivors L N 0 = Set.Icc 0 1
- LeanPool.Besicovitch.Example.survivors L N n.succ = LeanPool.Besicovitch.Example.survivors L N n ∩ LeanPool.Besicovitch.Example.avoid L (N + n + 1)
Instances For
The survivors have finite measure.
The recursive estimate for the measure of the survivors.
The sums ∑_{k < n} 1 / ((N + k) (L + 1)) diverge, by comparison with the harmonic series.
The measure of the survivors tends to zero.
The main theorems #
The two-sided avoiders are null. The points of [0, 1] at distance at least
margin L n from every level-n grid point, for all n ≥ N, form a null set.
Lipschitz pieces are null. A subset of [0, 1] on which Besicovitch's function is
Lipschitz has Lebesgue measure zero.