Exact unrestricted Boolean multiplicative complexity for four-term products #
The structural contradiction rules out eight gates. Together with the
algebraic seven-gate obstruction and the explicit nine-gate construction,
this closes the n = 4 theorem.
theorem
UnrestrictedBooleanMul.N4.normalizedEight_contradiction
{C : Circuit 8 8}
(h : NormalizedEight C)
:
The normalized eight-gate state is inconsistent: gate six is useful by the flag ledger and non-useful by first-jet saturation.
There is no unrestricted eight-AND circuit for four-term Boolean multiplication.
Every unrestricted circuit for Mul 4 has at least nine AND gates.