Certifying transmission from finitely many rank corners #
The transmission condition for an ASP permutation τ is indexed by the whole
lattice ℤ × ℤ. Two general facts collapse it to a finite check.
- Riemann. Every divisor satisfies
rank G E ≥ deg E - genus G, so a transmission row whose threshold is at mostτ.χ + a - bcosts nothing. - Chip transport. A single rank bound at one lattice point
(a₀, b₀)propagates to every other point, losing one unit for each chip that has to be removed:rank (D + a•u - b•v) ≥ r₀ - max 0 (a₀ - a) - max 0 (b - b₀).
Consequently a divisor satisfies the full transmission condition as soon as it
achieves finitely many corner bounds that, together with the Riemann line,
dominate the slipface of τ. This is the mechanism behind the classical
dictionary: for a Grassmannian τ whose diagram is a rectangle the corner list
has a single entry, and transmission becomes an ordinary Brill--Noether
condition BNExists G r d; the length of τ is exactly (r+1) * (g - d + r),
so ℓ(τ) ≤ g is the Brill--Noether inequality ρ ≥ 0.
Riemann and chip transport #
The Riemann inequality: rank is at least degree minus genus.
Corner certificates #
A corner is a lattice point together with a rank threshold.
Instances For
A corner list dominates τ when every transmission threshold is met by one
of three things: the trivial bound rank ≥ -1, the Riemann line, or transport
from one of the corners.
Equations
Instances For
Corner certificate. A divisor of the right degree that achieves every corner bound satisfies the full transmission condition.
Existence: the Brill--Noether dictionary #
A slipface dominated by the Riemann line alone is realized by every divisor of the correct degree. This covers exactly the ASP permutations of length zero.
One corner is an ordinary Brill--Noether condition. If a single corner
(a₀, b₀, r₀) dominates the slipface of τ, then transmission for τ follows
from BNExists at rank r₀ and the corresponding affine degree.
The converse for a corner that records the true slipface value: transmission
returns the Brill--Noether witness. Together with
transmissionExists_of_corner_of_BNExists this is an equivalence.
Dictionary. For a permutation whose slipface has a single dominating corner recording its true value, transmission on a twice-marked graph is equivalent to ordinary Brill--Noether existence, and in particular does not depend on the two marks.
The elementary range #
The Brill--Noether input of a single-corner permutation is elementary exactly in
the two ranges already available unconditionally: rank zero, and rectangle width
at most one. For a single-corner τ the corner rank r₀ and rectangle width
w₀ = g - d₀ + r₀ = b₀ - a₀ - τ.χ + r₀ satisfy ℓ(τ) = (r₀ + 1) * w₀, so
ℓ(τ) ≤ 3 forces r₀ = 0 or w₀ ≤ 1. The first genuinely new input appears at
ℓ(τ) = 4 with r₀ = 1 and w₀ = 2, which is the critical rank-one width-two
column W^1_{g-1}.
Transmission in the elementary Brill--Noether range.
Rank-zero corner: the transmission witness is an effective divisor.