return to top
source
For any i n : ℕ with i > 0 and i ≤ (n + 1) * i, we have that 1 / (n + 1) = i / ((n + 1) * i).
i n : ℕ
i > 0
i ≤ (n + 1) * i
1 / (n + 1) = i / ((n + 1) * i)