Derivative of the L^q functional along a line #
For u and v in L^q(μ) with q > 1, the map t ↦ ∫ |u + tv|^q is differentiable at 0,
with derivative q ∫ |u|^{q-2} u v. This is the constraint derivative of the direct method: the
subcritical minimiser of EllipticPdes.Embedding.exists_minimiser_of_lt lives on the unit sphere
of L^q, and its Euler-Lagrange equation is this derivative set against the derivative of the
H₀¹ norm.
The proof is differentiation under the integral sign.
hasDerivAt_integral_of_dominated_loc_of_deriv_le asks for a dominating function on a
neighbourhood of 0, and Hölder's inequality supplies one: the integrand's t-derivative is
bounded on |t| < 1 by q(|u| + |v|)^{q-1}|v|, whose first factor lies in L^{q/(q-1)} and whose
second lies in L^q. Mathlib's hasDerivAt_abs_rpow supplies the pointwise derivative, including
at the origin, where q > 1 makes |·|^q differentiable with derivative zero.
Main declarations #
EllipticPdes.Analysis.integrable_abs_rpow_sub_one_mul: the dominating function is integrable.EllipticPdes.Analysis.hasDerivAt_integral_abs_rpow: the derivative at0.
References #
James Guo, Partial Differential Equations, Section IX.1; L. C. Evans, Partial Differential Equations (2nd ed.), §8.1.2.
Integrability of the dominating function. With u and v in L^q, the product
(|u| + |v|)^{q-1}|v| is integrable: the first factor lies in L^{q/(q-1)} and the second in
L^q, whose reciprocals sum to one.
Derivative of the L^q functional along a line. For u and v in L^q(μ) with
q > 1, the map t ↦ ∫ |u + tv|^q is differentiable at 0 with derivative
q ∫ |u|^{q-2} u v.