The five-point obstruction #
The four-point catalogue confines a chain configuration to one adjacent pair {c, 3 * c} and
forces a common anchor. What survives is a very rigid picture: four points at squared distance
c from a common centre, with pairwise squared distances c or 3 * c.
no_four_on_circle rules that picture out. Writing u i for the vector from the centre to the
i-th point, the hypotheses give ⟪u i, u i⟫ = c and ⟪u i, u j⟫ = ± c / 2. Singularity of
every three-vector Gram matrix in the plane forces each triple product ⟪u i, u j⟫ ⟪u i, u k⟫ ⟪u j, u k⟫ to equal -c ^ 3 / 8, and then the explicit combination `c • u₁ - 2 ⟪u₁, u₂⟫ • u₂
- 2 ⟪u₁, u₃⟫ • u₃ - 2 ⟪u₁, u₄⟫ • u₄
has squared length-2 * c ^ 3 < 0`.
This is the five-point Gram obstruction in its scale-free form.
Singularity of the three-vector Gram matrix pins the triple product of the three inner products.
No four points on a circle. Four points at squared distance c > 0 from a common
centre cannot have all six pairwise squared distances in {c, 3 * c}.
The five-point obstruction. Five plane points whose ten squared distances are all c
times a nonnegative power of three, with c realised by the edge A B, do not exist. Since
IsChainValue c x forces c ≤ x, the hypothesis sqDist A B = c says exactly that A B is a
shortest edge.