Erdős Problem #137: the sextic (g = 6) crude block route — sharp threshold n > k^3 #
This module instantiates the generic crude (non-smooth) block route master_ineq_crude_g
(BlockFramework, PART E) at the block length g = 6. The crude master inequality reads
n ^ (6 - 2) ≤ k ^ (2 * 6), i.e. n ^ 4 ≤ k ^ 12, equivalently n ≤ k ^ 3. So under the sextic
block radical hypothesis BlockRadLB6, for k ≥ 6 and n > k^3 the product F k n is not
powerful (not_powerful_of_large_g6); for each fixed k ≥ 6, F k n is powerful for only
finitely many n (g6_crude_finiteness).
Why g = 6 #
The crude exponent is 2g/(g-2) = 2 + 4/(g-2), an integer exactly when (g-2) ∣ 4, i.e. precisely
for g ∈ {3, 4, 6} — giving k^6 (JointFiniteness), k^4 (QuarticCrude), and k^3 here. So
g = 6 is the last (largest) block length with an integer crude exponent, and k^3 is the
sharpest clean integer-exponent crude threshold this route reaches: beyond g = 6 the crude
exponent stays non-integer and only decreases toward k^2 as g → ∞ (e.g. g = 10 → k^{2.5}).
Like all crude thresholds this is fully explicit — no o(1), no unformalized Mertens input —
but it costs a correspondingly higher-degree block radical input: BlockRadLB6 is the
(F k n)^{5/6} ≤ ∏ rad bound over sextic blocks, with the g-dependent abc/Langevin constant (the
known radical-method ceiling: a sharper exponent for a worse constant). k^3 is comfortably below
the k^5 unconditional squarefree ceiling, so it too is a valid high-n input for the
squarefree-counting reduction.
What is proved (no sorry, only Mathlib's three axioms) #
not_powerful_of_large_g6:BlockRadLB6 → 6 ≤ k → k^3 < n → ¬ Powerful (F k n)— the headline.g6_crude_finiteness:BlockRadLB6 → 6 ≤ k → {n | 1 ≤ n ∧ Powerful (F k n)}.Finite.
The ONLY hypothesis is BlockRadLB6 (the g = 6 instance of BlockRadLBg); it is a premise, not
an axiom, so it does not appear in any axiom footprint.
(H, g = 6) Sextic block radical lower bound (abc-extremal form). Langevin/abc applied to
each squarefree sextic block g(m) = m(m+1)⋯(m+5), assembled over the ⌊k/6⌋ blocks:
(F k n)^{5/6} ≤ ∏ rad over sextic blocks. The g = 6 instance of BlockRadLBg; the exponent
5/6 = (6-1)/6 and the guard 6 ≤ k matches g ≤ k.
Equations
- Erdos137.BlockRadLB6 = ∀ (k n : ℕ), 6 ≤ k → 1 ≤ n → ↑(Erdos137.F k n) ^ (5 / 6) ≤ ↑(∏ j ∈ Finset.range (k / 6), Erdos137.rad (Erdos137.F 6 (n + 6 * j)))
Instances For
BlockRadLB6 is exactly the g = 6 instance of the generic BlockRadLBg (the exponents
5/6 and (6-1)/6 agree, and the guard 6 ≤ k matches g ≤ k).
The g = 6 block objects as literal instances of the generic framework #
The sextic block product B6 k n: the g = 6 instance of the generic Bg.
Equations
- Erdos137.B6 k n = Erdos137.Bg 6 k n
Instances For
overlap6 p is the number of sextic blocks p divides: the g = 6 instance of overlapg.
Equations
- Erdos137.overlap6 k n p = Erdos137.overlapg 6 k n p
Instances For
The over-count W6 k n: the g = 6 instance of the generic Wg.
Equations
- Erdos137.W6 k n = Erdos137.Wg 6 k n
Instances For
The sharp sextic crude headline (threshold k^3) #
Sextic crude headline. Under BlockRadLB6, for k ≥ 6 and n > k^3, F k n is not
powerful. From the crude master inequality n^4 ≤ k^12 (= master_ineq_crude_g 6): k^3 < n
forces k^12 = (k^3)^4 < n^4, contradiction.