Incremental derivatives #
Differentiability and derivative formulas for the maps t ↦ f⁽ᵏ⁾(t · x) and their
finite sums, used to differentiate the exponential factors in Niven's argument.
theorem
differentiableAt_mul_const_ofReal
(x : ℂ)
(t : ℝ)
:
DifferentiableAt ℝ (fun (t : ℝ) => ↑t * x) t
theorem
differentiableAt_comp_mul_real
(f : ℂ → ℂ)
(x : ℂ)
(t : ℝ)
(hf : DifferentiableAt ℂ f (↑t * x))
:
DifferentiableAt ℝ (fun (t : ℝ) => f (↑t * x)) t
If f is differentiable at t * x, then u ↦ f(u * x) is differentiable at t.
theorem
differentiableAt_exp_neg_mul
(x : ℂ)
(t : ℝ)
:
DifferentiableAt ℝ (fun (t : ℝ) => Complex.exp (-(↑t * x))) t
For x ∈ ℂ, the map t ↦ e^(-(t * x)) is differentiable at t.
theorem
continuousWithinAt_iteratedDeriv_comp_mul
(f : ℂ → ℂ)
(x : ℂ)
(n : ℕ)
(t : ℝ)
(hderiv : DifferentiableAt ℂ (iteratedDeriv n f) (↑t * x))
:
ContinuousWithinAt (fun (t : ℝ) => iteratedDeriv n f (↑t * x)) (Set.uIcc 0 1) t
If f^(n) is differentiable at t * x, then t ↦ f^(n)(t * x) is continuous on
[0, 1] at t.
theorem
differentiableAt_iteratedDeriv_comp_mul
(f : ℂ → ℂ)
(x : ℂ)
(k : ℕ)
(t : ℝ)
(hderiv : DifferentiableAt ℂ (iteratedDeriv k f) (↑t * x))
:
DifferentiableAt ℝ (fun (t : ℝ) => iteratedDeriv k f (↑t * x)) t
If f⁽ᵏ⁾ is differentiable at t * x, then t ↦ f⁽ᵏ⁾(t * x) is differentiable at t.
theorem
deriv_iteratedDeriv_comp_mul
(f : ℂ → ℂ)
(x : ℂ)
(k : ℕ)
(t : ℝ)
(hderiv : DifferentiableAt ℂ (iteratedDeriv k f) (↑t * x))
:
If f⁽ⁱ⁾ is differentiable at t * x, then d/dt f⁽ᵏ⁾(t * x)) = x * f⁽ᵏ⁺¹⁾(t * x).
theorem
differentiableAt_sum_iteratedDeriv
(f : ℂ → ℂ)
(x : ℂ)
(n : ℕ)
(t : ℝ)
(hderiv : ∀ k ≤ n, DifferentiableAt ℂ (iteratedDeriv k f) (↑t * x))
:
DifferentiableAt ℝ (fun (t : ℝ) => ∑ k ∈ Finset.range (n + 1), iteratedDeriv k f (↑t * x)) t
If f⁽ᵏ⁾ is differentiable at t * x for every k ≤ n, then
t ↦ ∑ₖ₌₀ⁿ f⁽ᵏ⁾(t * x) is differentiable at t.
theorem
sum_deriv_iteratedDeriv_comp_mul
(f : ℂ → ℂ)
(x : ℂ)
(n : ℕ)
(t : ℝ)
(hderiv : ∀ k ≤ n, DifferentiableAt ℂ (iteratedDeriv k f) (↑t * x))
:
deriv (fun (t : ℝ) => ∑ i ∈ Finset.range (n + 1), iteratedDeriv i f (↑t * x)) t = ∑ i ∈ Finset.range (n + 1), x * iteratedDeriv (i + 1) f (↑t * x)
If f⁽ᵏ⁾ is differentiable at t * x for every k ≤ n, then
d/dt ∑ᵢ₌₀ⁿ f⁽ⁱ⁾(t * x)) = ∑ᵢ₌₀ⁿ x * f⁽ⁱ⁺¹⁾(t * x).