Third Harmonic Extraction #
This module focuses on the Fourier domain analysis of the weighted sieve sums, specifically expanding the hit counts into frequencies and isolating the main terms and the key third harmonic contribution.
Define $\hat{W}(h)$ (Fourier Transform of the Weight): Define $\hat{W}(h)$ as the Discrete Fourier Transform of the weight function $W(x)$ over $\mathbb{Z}/q\mathbb{Z}$: $$ \hat{W}(h) = \frac{1}{q} \sum_{x=0}^{q-1} W(x) e^{-2\pi i h x / q} $$
Equations
- KrafftSieve.wHat n W h = 1 / ↑(KrafftSieve.q n) * ∑ x : ZMod (KrafftSieve.q n), ↑(W x) * Complex.exp (-2 * ↑Real.pi * Complex.I * ↑(h.val * x.val) / ↑(KrafftSieve.q n))
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Define $\hat{g}_i(h)$ (Fourier Transform of the Local Hit): Define $\hat{g}_i(h)$ as the Discrete Fourier Transform of the local hit function $g_i(x)$: $$ \hat{g}_i(h) = \frac{1}{q} \sum_{x=0}^{q-1} g_i(x) e^{-2\pi i h x / q} $$
Equations
- KrafftSieve.gHat n i h = 1 / ↑(KrafftSieve.q n) * ∑ x : ZMod (KrafftSieve.q n), ↑(KrafftSieve.g n i x) * Complex.exp (-2 * ↑Real.pi * Complex.I * ↑(h.val * x.val) / ↑(KrafftSieve.q n))
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Compact Support Equivalence
Assume the weight function is strictly supported inside the interval: $\forall x \notin \mathcal{A}_n, W(x) = 0$. Prove that the interval sum $sum1(n, W)$ is equivalent to the full space sum, which yields the zero-frequency Fourier coefficient: $$ sum1(n, W) = \sum_{x \in \mathbb{Z}/q\mathbb{Z}} W(x) = q \hat{W}(0) $$
Plancherel's Theorem for the custom Fourier transform definition: $$ \sum_{x} f(x) \overline{g(x)} = q \sum_{h} \hat{f}(h) \overline{\hat{g}(h)} $$
The Plancherel Hit Expansion Using the compact support of $W(x)$ and admitting Plancherel's theorem for the inner product of $W(x)$ and $g_i(x)$, expand the weighted hit count $sum2(n)$ into the Fourier domain: $$ sum2(n) = q \sum_{i=1}^w \sum_{h=0}^{q-1} \hat{W}(h) \overline{\hat{g}_i(h)} $$
The Exact Krafft Cosine
Using the definition $r^K_i = \lfloor(p_i+1)/6\rfloor$, admit that for all primes $p_i \ge 5$, the cosine at the third harmonic evaluates exactly to the negative cosine of a microscopic angle: $$ \cos\left( \frac{2\pi \cdot 3 \cdot r^K_i}{p_i} \right) = -\cos\left( \frac{\pi}{p_i} \right) $$
The Third Harmonic Extraction
Admit that for a strategically chosen weight function $W(x)$ where $\hat{W}(h)$ is concentrated strictly at $h=0$ and the third harmonics $h = 3q/p_i$, the Resonant Sieve Equation simplifies to: $$ sum2(n, W) = sum1(n, W) \sum_{i=1}^w \frac{2}{p_i} - q \sum_{i=1}^w \hat{W}\left(3 \frac{q}{p_i}\right) \frac{2}{p_i} \cos\left( \frac{\pi}{p_i} \right) $$
Sum of reciprocals of primes in the sieve window
Equations
- KrafftSieve.hSpec n = ∑ p ∈ KrafftSieve.primeWindow n, 1 / ↑p
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The main term of the sieve: 2H(n)
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The resonance strength for a single prime p: cos(π/p)
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The total resonance capacity: Σ (2/p)·cos(π/p)
Equations
- KrafftSieve.resonanceCapacity n = ∑ p ∈ KrafftSieve.primeWindow n, 2 / ↑p * KrafftSieve.resonanceStrength p
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The Harmonic Deficit (Parity Barrier Collision) The resonance capacity of any purely one-dimensional 3rd harmonic weight system is strictly overpowered by the sieve aggregate main density. This formalizes the collision with the Sieve Parity limit.