Null-Homologous Curves: Definitions and Convexity Bridge #
A closed piecewise C^1 immersion is null-homologous in an open set U when its winding number around every point outside U is zero. This is the topological condition required by the generalized residue theorem of Hungerbuhler-Wasem.
Main definitions #
IsNullHomologous-- null-homologous curve in an open set
Main results #
ftc_piecewise_contour-- FTC for piecewise C¹ contoursintegrand_intervalIntegrable_of_avoids-- integrability of winding integrandisNullHomologous_of_convex-- every closed curve in a convex open set is null-homologous (bridge lemma)
A closed piecewise C^1 immersion gamma is null-homologous in an open set U if:
- gamma is a closed curve
- gamma lies entirely in U
- The winding number of gamma around every point outside U is zero.
This matches the definition in Hungerbuhler-Wasem (arXiv:1808.00997v2).
- closed : γ.IsClosed
Instances For
FTC for piecewise C¹ contours (induction on partition points): on any
sub-interval [a', b'] whose endpoints belong to the partition and that
contains at most n interior partition points, the integral of
f(γ(t)) · γ'(t) equals F(γ(b')) - F(γ(a')), provided F ∘ γ is
continuous, its derivative equals the integrand off the partition, and the
integrand is interval-integrable.
Fundamental theorem of calculus for piecewise C¹ contours: if F is a
primitive of f on U (i.e. HasDerivAt F (f z) z for every z ∈ U) and
γ is a piecewise C¹ curve lying in U, then
∫_γ f(z) dz = F(γ(b)) - F(γ(a)).
The integrand (γ(t) - z)⁻¹ · γ'(t) is interval-integrable whenever z
is not in the image of γ. The proof uses compactness of [a, b] to bound
‖(γ(t) - z)⁻¹‖ and the piecewise C¹ bound on ‖γ'(t)‖.
Every closed curve in a convex open set is null-homologous.
The proof uses:
generalizedWindingNumber_eq_classical_awayto reduce the PV winding number to a classical contour integral (since z is not on the curve).holomorphic_convex_primitiveto obtain a primitive F of w |-> (w - z)^{-1} on the convex set U.- The fundamental theorem of calculus to evaluate the integral as F(gamma(b)) - F(gamma(a)) = 0 (since gamma is closed).