Per-Term PV Vanishing and CPV Helpers #
Per-term PV vanishing for higher-order polar terms (L4), Laurent circle integrals, multi-point CPV, holomorphic CPV vanishing, and assembly helpers.
Main results #
pv_higher_order_term_tendsto_zero: single-crossing higher-order PV → 0multipoint_pv_zpow_tendsto_zero: multi-point CPV of zpow → 0holomorphic_cpv_tendsto_zero_on_convex: holomorphic CPV → 0 on convex domainstendsto_cpv_of_continuousOn_zero_integral: CPV → 0 for continuous functions with zero integral
L4: Per-term PV vanishing for higher-order polar terms #
The cutoff integral of a/(γ(t)-s)^{m}·γ'(t) (with m ≥ 2) tends to 0 under
the angle condition + flatness, using FTC + boundary vanishing (L3).
The FTC reduces the cutoff integral to boundary terms (γ(t_exit)-s)^{1-m}/(1-m)
at the exit points of the ε-ball. These boundary terms are exactly the w^k
from L3 with k = 1-m ≤ -1, and flatness of order m gives
n + k = m + (1-m) = 1 ≥ 1.
For a single crossing at t₀ with angle α, exponent m ≥ 2, and
flatness of order m: if (m-1) · α ∈ 2πℤ, then the PV cutoff integral
of (γ-s)^{-m} · γ' tends to 0.
This combines FTC telescoping (L1) with boundary vanishing (L3). The flatness
hypothesis is essential: without it, the boundary terms (γ-s)^{1-m} at the
ε-cutoff points grow as ε^{1-m} → ∞ and the angle condition alone cannot
compensate. With flatness of order m, the direction convergence rate is
o(ε^{m-1}), which exactly cancels the ε^{1-m} divergence.
CPV integrand of f minus CPV integrand of g equals CPV integrand of f - g,
pointwise, because both use the same indicator set {t : ∃ s ∈ S0, ‖γ t - s‖ ≤ ε}.
Sublemma 1: Residue equals leading Laurent coefficient #
Sublemma 1: The residue of f at s equals the leading Laurent coefficient a₀.
Given the Laurent expansion f(z) = g(z) + Σ_{k=0}^{N-1} aₖ/(z-s)^{k+1} near s,
with g analytic at s, the circle integral definition of residueAt gives
residueAt f s = a₀.
Proof strategy: On a small circle of radius r around s:
∮ g = 0by Cauchy (g analytic → differentiable on disk)∮ (z-s)^{-(k+1)} = 0fork ≥ 1(byintegral_sub_zpow_of_ne, exponent ≠ -1)∮ (z-s)⁻¹ = 2πi(byintegral_sub_center_inv)- So
∮ f = a₀ · 2πi, henceresidueAt f s = (2πi)⁻¹ · a₀ · 2πi = a₀.
The derivative deriv γ.toFun is AEStronglyMeasurable on Icc γ.a γ.b for
any PiecewiseC1Immersion γ, because it is continuous off the finite partition set.
A.e. t in the integration interval Ι γ.a γ.b does not land on any
point of S0 under γ, because each crossing set is finite (hence null).
Sublemma 2: Multi-point CPV of higher-order pole term → 0 #
Sublemma 2: The multi-point CPV integral of (z-s)^{-m} tends to 0
for m ≥ 2, given flatness of order m and the angle condition.
This extends pv_higher_order_term_tendsto_zero from single-point to
multi-point cutoff. The difference between multi-point and single-point
cutoffs is supported on a set where (z-s)^{-m} is bounded (far from s,
near some other s' ∈ S0) and whose measure tends to 0.