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LeanPool.LeanModularForms.ValenceFormula.PVChain.ArcContribution

Arc Contribution to the PV Chain #

Proves that the ε-truncated arc integral of f'/f along the FD boundary tends to -(2πik/12) as ε → 0⁺.

The proof uses S-symmetry: the modular S-transformation z ↦ -1/z is an isometry on the unit circle, and the logDeriv functional equation gives F(4-t) + F(t) = -k·(iπ/6)·indicator(t) pointwise. Integrating and using the change of variables t ↦ 4-t yields 2·I(ε) = -k·(iπ/6)·m(ε), where m(ε) → 2.

Main Results #

LogDeriv S-transformation #

S-isometry on unit circle #

theorem S_isometry_unit_circle (z w : ) (hz : z = 1) (hw : w = 1) :
-1 / z - -1 / w = z - w

Arc S-reversal #

theorem fdBoundary_arc_S_reverse (H t : ) (ht : t Set.Ioo 1 3) :
fdBoundaryH H (4 - t) = -1 / fdBoundaryH H t

Arc indicator symmetry #

Integrability of CPV integrand on arc #

Arc preimage subsingleton #

S-symmetry identity for arc CPV integral #

Non-excluded measure tends to 2 #

theorem arc_non_excluded_measure_tendsto (S : Finset UpperHalfPlane) (H : ) :
Filter.Tendsto (fun (ε : ) => (t : ) in 1..3, if ssArcOfS S, fdBoundaryH H t - s ε then 0 else 1) (nhdsWithin 0 (Set.Ioi 0)) (nhds 2)

Arc CPV contribution tends to -(2πik/12) #

Bridge: sArcOfS S ∪ sVertOfS S → sArcOfS S on arc interval #

Final bridge for Assembly.lean #

theorem tendsto_pvIntegral_arc_bridge {k : } (f : ModularForm (Subgroup.map (Matrix.SpecialLinearGroup.mapGL ) (CongruenceSubgroup.Gamma 1)) k) (S : Finset UpperHalfPlane) {H : } (_hH : 3 / 2 < H) (h_oncurve_arc : tSet.Ioo 1 3, modularFormCompOfComplex f (fdBoundaryH H t) = 0fdBoundaryH H t (sArcOfS S)) :
Filter.Tendsto (fun (ε : ) => (t : ) in 1..3, pvIntegrand f (fdBoundaryH H) (sArcOfS S sVertOfS S) ε t) (nhdsWithin 0 (Set.Ioi 0)) (nhds (-(2 * Real.pi * Complex.I * (k / 12))))