Mayer–Vietoris base case: H₁(S¹; ℤ) ≅ ℤ #
We compute the integral first homology of the circle S¹ by the singular
Mayer–Vietoris sequence applied to the two-punctured cover specialized from the
recursive step file (SphereHomologyMVStep.lean), with n = 0:
U = S¹ \ {north},V = S¹ \ {south}are contractible;U ∩ V(the equatorial band) is homotopy equivalent toS⁰.
Around degree 1 the sequence reads
H₁(U) ⊕ H₁(V) → H₁(S¹) → H₀(U ∩ V) → H₀(U) ⊕ H₀(V).
The left term vanishes (contractibility), so the connecting map identifies
H₁(S¹) ≅ ker(H₀(U ∩ V) → H₀(U) ⊕ H₀(V)). Using the augmentation isomorphism
H₀(contractible) ≅ ℤ (SingularH0PathConnected.lean), that kernel coincides
with the kernel of the augmentation H₀(U ∩ V) → ℤ, i.e. with the reduced
zeroth homology H_tilde₀(S⁰) ≅ ℤ.
The result sphereTopHomologyIsoOne : SphereTopHomologyIso 1 supplies the
base field of SphereSuspensionTower.
Setup for the circle cover (the n = 0 specialization) #
The upper-punctured open cover member.
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The lower-punctured open cover member.
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The equatorial band S¹ \ {north, south} as a subset.
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The Mayer–Vietoris left map on H₀, H₀(U ∩ V) → H₀(U) ⊕ H₀(V).
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Reduced H₀(S⁰) ≅ ℤ #
Algebra helper. The kernel of a surjection from a rank-2 finite free
ℤ-module onto ℤ is isomorphic to ℤ.
The kernel of the band augmentation is ℤ #
The kernel of the band augmentation H₀(U ∩ V) → ℤ is isomorphic to ℤ,
using the homotopy equivalence U ∩ V ≃ S⁰ and reducedH0_sphere0_iso.
The Mayer–Vietoris kernel identity #
Joint monomorphism of the homology biproduct projections. An element of
H₀(X₂) is zero iff both of its biproduct components vanish.
The Mayer–Vietoris kernel coincides with the reduced-H₀ kernel.
ker(H₀(U ∩ V) → H₀(U) ⊕ H₀(V)) ≅ ker(H₀(U ∩ V) → ℤ).
Assembling the Mayer–Vietoris connecting isomorphism #
The base case #
H₁(S¹; ℤ) ≅ ℤ (as a Nonempty package).
The base case of the sphere suspension tower: H₁(S¹; ℤ) ≅ ℤ.