Modified Bessel Function K₁ #
This file defines the modified Bessel function K₁(z) via its integral representation and establishes key properties needed for the free covariance in AQFT.
Main definitions #
besselK1- The modified Bessel function K₁(z) = ∫₀^∞ exp(-z cosh(t)) cosh(t) dtbesselK1_properTime- Alternative proper-time representation: K₁(z) = (z/2) ∫₀^∞ t^{-2} exp(-t - z²/(4t)) dt
Main results #
besselK1_pos- K₁(z) > 0 for z > 0besselK1_asymptotic- Asymptotic bound K₁(z) ≤ √(π/(2z)) · exp(-z) · 2 for z ≥ 1besselK1_eq_properTime- Equivalence of cosh and proper-time representationsschwingerIntegral_eq_besselK1- Identity connecting Schwinger integral to K₁
Notes #
The cosh integral representation is particularly useful because:
- It's manifestly real and positive for positive arguments
- The integrand decays exponentially in t for any z > 0
- It directly shows the analytic structure in z
For the massive scalar field in 4D Euclidean space, the exact formula is: C(x,y) = (m / (4π² |x-y|)) · K₁(m |x-y|)
K₁ is continuous on (0, ∞). This follows from dominated convergence since the integrand z ↦ exp(-z cosh(t)) cosh(t) is continuous in z and dominated by exp(-ε cosh(t)) cosh(t) for z ≥ ε, which is integrable.
The formal proof uses MeasureTheory.continuousOn_of_dominated_of_compact: for z in compact K ⊆ (0, ∞), bound by exp(-min(K) * cosh(t)) * cosh(t).
K₁ has exponential decay: K₁(z) ≤ (sinh(1) + 2) · exp(-z) for z ≥ 1. This bound is sufficient for proving integrability of the free covariance kernel. The proof uses the same technique as besselK1_mul_self_le but for z ≥ 1.
For z ∈ (0, 1], we have z · K₁(z) ≤ cosh(1) + 2. This follows from splitting the integral at t = 1:
- On [0,1]: z · ∫₀¹ exp(-z cosh t) cosh t dt ≤ z · cosh(1) ≤ cosh(1)
- On [1,∞): z · ∫₁^∞ exp(-z cosh t) cosh t dt ≤ 2 (via exponential bound)
The radial integrand r² K₁(mr) is integrable on (0, ∞) for m > 0.
Mathematical justification:
- Near 0: K₁(mr)
1/(mr), so r² K₁(mr)r/m, which is integrable near 0 - At ∞: K₁(mr) ~ e^{-mr}/√(mr), so r² K₁(mr) decays exponentially
This is a key ingredient for showing the free covariance kernel is L¹ in 4D.
Symmetry lemma: the full-line integral of exp(-u) * exp(-z cosh u) equals twice the half-line cosh integral, which is 2 * K₁(z).
∫_{-∞}^∞ exp(-u) * exp(-z cosh u) du = 2 ∫_0^∞ cosh(u) * exp(-z cosh u) du
This follows from splitting at 0 and using cosh(-u) = cosh(u).
Key identity connecting the Schwinger proper-time integral to K₁: ∫₀^∞ t^{-2} exp(-m²t - r²/(4t)) dt = (4m/r) · K₁(mr)
This is proven directly via the substitution t = (r/(2m)) exp(u), which transforms the integral to the cosh representation of K₁.