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LeanPool.OperatorTheory.Operator.Crouzeix.ProductSymmetrizedAlignment

Universal symmetrization forces scalar-circle alignment #

The off-center scalar-circle example shows that a sharp symmetrized estimate for one polynomial does not force the corresponding auxiliary product bound. The universal L4.2d family is genuinely stronger. For the scalar operator a • 1, applying it to X - C a forces the circle center to be a: the polynomial vanishes on the numerical range, while its circle auxiliary detects the center displacement. Once aligned, the normal-operator product theorem gives the literal L4.2e bound for every polynomial.

Main declarations #

If the sharp fixed-control-set symmetrized bound holds for every polynomial at the scalar operator a • 1, an enclosing circle must be centered at a. Testing with X - C a detects any displacement.

On a scalar operator, the universal sharp symmetrized family forces circle alignment and therefore implies the literal sharp auxiliary product bound for every polynomial.