Universal symmetrization forces scalar-circle alignment #
The off-center scalar-circle example shows that a sharp symmetrized estimate
for one polynomial does not force the corresponding auxiliary product bound.
The universal L4.2d family is genuinely stronger. For the scalar operator
a • 1, applying it to X - C a forces the circle center to be a: the
polynomial vanishes on the numerical range, while its circle auxiliary
detects the center displacement. Once aligned, the normal-operator product
theorem gives the literal L4.2e bound for every polynomial.
Main declarations #
circle_center_eq_scalar_of_forall_crouzeix_symmetrized_boundproves the alignment forced by universal fixed-control-set symmetrization.norm_aeval_mul_crouzeixPolynomialAuxiliaryOperator_smul_one_le_of_forall_symmetrized_boundderives the actual auxiliary product bound for every polynomial in this coupled scalar branch.
If the sharp fixed-control-set symmetrized bound holds for every
polynomial at the scalar operator a • 1, an enclosing circle must be
centered at a. Testing with X - C a detects any displacement.
On a scalar operator, the universal sharp symmetrized family forces circle alignment and therefore implies the literal sharp auxiliary product bound for every polynomial.