Giles Gardam's result #
The proof of the theorem 𝔽₂[P] has non-trivial units. Together with the main
result of TorsionFree -- that P is torsion-free, this completes the formal
proof of Gardam's theorem that Kaplansky's Unit Conjecture is false.
Preliminaries #
An element of a free module is trivial but not zero if it is supported on one basis vector.
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The statement of Kaplansky's Unit Conjecture: The only units in a group ring, when the group is torsion-free and the ring is a field, are the trivial units.
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The finite field on two elements.
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The main constants of the group P.
The first kernel generator of the Promislow group.
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The second kernel generator of the Promislow group.
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The third kernel generator of the Promislow group.
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The first nontrivial quotient generator of the Promislow group.
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The second nontrivial quotient generator of the Promislow group.
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Verification #
The main verification of Giles Gardam's result.
A proof that the unit is non-trivial.
The fact that the counter-example α is in fact a unit of the group ring 𝔽₂[P]
is verified by computing the product of α with its inverse α' and checking that the
result is (1 : 𝔽₂[P]).
The computational aspects of the group ring implementation and the Metabelian construction are used here.
The product of Gardam's unit and its inverse is one.
The product of Gardam's inverse and its unit is one.
Giles Gardam's result - Kaplansky's Unit Conjecture is false.
We check that our definition of "trivial but not zero" is correct by showing it equivalent to a more direct definition.
Triviality of p : R[G] coincides with the direct definition p = a ⬝ g, a ≠ 0.