Monotonicity of the elementary bound in the degree #
Sendov.U bounds Sendov.R for every n ≥ 5. Here it is reduced to a single inequality
in α alone, by showing that U n α is essentially decreasing in n on n ≥ 101.
Two features of the bound make this cheaper than it looks.
First, the sharp Beta constant collapses. The exponent is r = (n-4)/2, so
(r+1)(r+2)(r+3)(r+4) = (n-2) n (n+2) (n+4) / 16,
and the n (n-2) in it cancels the n (n-2) in the prefactor of Sendov.R exactly. The
first tail term is therefore the rational function
T1 n α = 24 (n-1-2α)² / ((3+α) c⁴ (n-1)(n+2)(n+4)),
with no factorial-like growth left to control. (Had the cruder constant 6/r⁴ of the
informal write-up been used, no such cancellation would occur and the corresponding step
would need the degree-8 positivity certificate recorded there.)
Second, the surviving real power is a square: writing b = √B, the second tail term is
T2 n α = A² n (n-1)(n-2)/(16(3+α)) · b ^ (n-4) with a natural exponent, so the geometric
decay can be run as an ordinary induction on n rather than as an estimate on rpow.
The two certificates #
T1 is not monotone in n by itself — at α = 17 the factor
(n-1-2α)²/((n-1)(n+2)(n+4)) increases up to n ≈ 108 — so it is bounded by its value at
n = 101 only after a 1% allowance, which the c⁴ in the denominator more than pays for.
That allowance is Sendov.tail1_poly, a Bernstein certificate on 0 ≤ α ≤ 17. Its top
coefficient is the only one in this development that is not a positive combination of
powers of the degree offset; it is handled by completing the square, its quadratic part
having negative discriminant.
Sendov.tail2_poly is the geometric step, and is an ordinary all-positive certificate.
Main statements #
Sendov.U_eq:Uin closed form,T1 + T2plus four elementary terms;Sendov.T1_le,Sendov.T2_le: the two tail bounds atn = 101;Sendov.U_le_Ut:U n α ≤ Ut αforn ≥ 101, whereUtinvolves nonand norpow.
The two polynomial certificates #
The allowance for the first tail term: on 0 ≤ α ≤ 17 and N = 100 + j ≥ 100,
(N-2α)² / (N (N+3)(N+5)) ≤ (101/100) (100-2α)² / (100 · 103 · 105).
A Bernstein certificate in α on [0,17], whose coefficients are polynomials in j. The
top one, 439956 j³ + 27356448 j² - 366591060 j + 4711014000, has a negative linear
coefficient; it is nonnegative because its quadratic part has negative discriminant.
The geometric step for the second tail term: on 0 ≤ α ≤ 17 and n = 101 + k ≥ 101,
12 A_{n+1}² (n+1) n (n-1) ≤ 13 A_n² n (n-1)(n-2),
after clearing the denominators n² and (n-1)² of A_{n+1} and A_n. Together with
√B ≤ 12/13 this makes the step ratio less than one. A Bernstein certificate in α on
[0,17] with all coefficients positive combinations of powers of k.
The closed form of U #
The sharp Beta constant, factored. This is the cancellation that makes T1 rational:
(r+1)(r+2)(r+3)(r+4) = (n-2) n (n+2)(n+4)/16 at r = (n-4)/2.