The sharp Euclidean growth inequality 2 qₙ ≤ qₙ₊₄ (K = 4) via Haynes–Marklof Theorem 8 #
This sharpens euclidean_growth_five (2 qₙ ≤ qₙ₊₅, the planar packing count) to the sharp
2 qₙ ≤ qₙ₊₄, the input to the sharp Euclidean five-distance theorem g₂ ≤ 5. The five-vector
configuration r(qₙ), …, r(qₙ₊₄) is admissible for the bare packing count (5 vectors pairwise > π/3
do fit), so the extra structure of Haynes–Marklof Theorem 8 (FiveDistance.hm_theorem8) is used:
the
shortest record r(qₙ₊₄) cannot lie in the open cone of two others, because that would force
‖r(qₙ₊₄) − vⱼ − vₖ‖ < ‖vₖ‖ (FiveDistanceHM.cone_exclusion) while the best-approximation property
(hbest, the index difference lies in (0, qₖ)) forces ‖r(qₙ₊₄) − vⱼ − vₖ‖ > ‖vₖ‖. Axiom-clean.
The sharp Euclidean growth inequality, K = 4 (Haynes–Marklof Theorem 8). For a
best-L²-approximation sequence (q, p) of α : Fin 2 → ℝ with the record/monotonicity
hypotheses,
the denominators at least double every four steps: 2 qₙ ≤ qₙ₊₄.