The auxiliary kernel G, and why it is constant #
G u = f_0 u + integral over [-1/2, 1/2] of |u - v| f_0 v.
The heart of the computation: the modulus kernel differentiates twice to 2 f_0 u while
f_0'' = -2 f_0, so G'' = 0 and G is affine; being even, it is constant.
The auxiliary kernel G(u) = f₀(u) + ∫_{-1/2}^{1/2} |u - v| f₀(v) dv, which is constant on
[-1/2, 1/2].
Equations
- ZetaZeros.extremalG u = ZetaZeros.extremalTest u + ∫ (v : ℝ) in -1 / 2..1 / 2, |u - v| * ZetaZeros.extremalTest v
Instances For
Antiderivatives for the modulus kernel #
Antiderivative for the shifted kernel: for fixed u,
d/dv [u·sin(√2 v)/√2 − (v·sin(√2 v)/√2 + cos(√2 v)/2)] = (u − v)·cos(√2 v).