A single low-degree vertex already forces algConn ≤ 2 #
If G has a vertex u of degree ≤ 2 and there is at least one vertex outside
{u} ∪ N(u), then algConn G ≤ 2.
Certificate: with C := N(u) (|C| = deg u ≤ 2) and T := V ∖ ({u} ∪ C), take
x := |T|·e_u − 𝟙_T. Then ∑ x = 0, ∑ x² = |T|² + |T|, and the only edges that
contribute to the Laplacian form are the deg u edges u–C (each |T|²) and the
T–C edges (each 1); there are no u–T edges. Since every vertex of T meets
at most |C| ≤ 2 vertices of C, the T–C edge count is ≤ 2|T|, so
xᵀ L x = deg u · |T|² + e(T,C) ≤ 2|T|² + 2|T| = 2 ∑ x².
This closes every n ≤ 7 instance of the conjecture: m = 2(n-2) < 3n/2 for n ≤ 7
forces a vertex of degree ≤ 2. The open core is exactly the graphs with minimum
degree ≥ 3 (possible only for n ≥ 8).
If G has a vertex of degree ≤ 2 with a vertex outside its closed neighborhood,
then algConn G ≤ 2.