Example 1.11: the torsion order of a cycle #
A cycle graph, marked at its two junction vertices, is exactly a genus-one
banana B : Banana 1, marked at leftEndpoint B and rightEndpoint B, with
the two strand lengths B.length 0 and B.length 1 playing the role of the
paper's a and b.
The proof identifies the marked difference [rightEndpoint - leftEndpoint]
with (B.length 0) • w in the graph Jacobian, where w is the first
normalized coordinate step on strand 0 (bananaCoordinateStep B 0). Two
facts from the banana Jacobian presentation (Proposition 2.14) pin down the
order of w exactly:
- the diagonal relation (firing the shared left endpoint once) identifies
won strand1with-won strand0, so combining the two strand-length relations gives(B.length 0 + B.length 1) • w ~ 0; - conversely, the exact relation lattice of Proposition 2.14 (not just a
containment) shows that no smaller multiple of
wis principal, via a homomorphism toZMod (B.length 0 + B.length 1)that kills exactly the displayed relations.
Combining the two pins down the torsion order at
(B.length 0 + B.length 1) / gcd (B.length 0) (B.length 1), matching
eg:cycle.
The homomorphism (x0, x1) ↦ x0 - x1 from banana coordinates to
ZMod n. For n = a + b this kills exactly the displayed relations of a
genus-one banana's Jacobian presentation.
Equations
Instances For
Example 1.11 (eg:cycle), torsion order half: for a cycle graph
B : Banana 1, marked at its two junction vertices, the torsion order of
(leftEndpoint, rightEndpoint) is (a + b) / gcd a b with a = B.length 0,
b = B.length 1.
Example 1.11 (eg:cycle), all-submodularity half: a cycle graph is
connected of genus one with distinct marks, so every divisor is
submodular.
Example 1.11 (eg:cycle): a cycle graph, marked at its two junction
vertices, has k-general transmission at k = (a + b) / gcd a b, where a
and b are the lengths of the two paths joining the marks.