The scalars of a simple algebra #
For a commutative algebra object R whose only ideals are ⊥ and
⊤, multiplication by a nonzero even scalar is an isomorphism, so
the even part of the Γ-algebra of R is a field; and the odd part
of that Γ-algebra vanishes.
The mechanism is RS.mulBy: multiplication by an even scalar is a
module endomorphism of R (RS.mul_comp_mulBy), so its kernel and
its image are ideals (RS.isIdeal_kernelSubobject_mulBy,
RS.isIdeal_imageSubobject_mulBy). Simplicity forces the kernel to
be ⊥ and the image to be ⊤, whence the endomorphism is an
isomorphism (RS.isIso_mulBy_of_simple) and the preimage of the
unit inverts the scalar (RS.exists_inverse_of_simple).
The odd part goes the same way. An odd element f acts on R by
RS.gmul f (𝟙 R), whose image is an ideal for the same reason; an
odd element squares to zero, so that action kills its own image, and
under either alternative of simplicity the action vanishes
(RS.hom_oddLine_eq_zero_of_simple).
Convolution against the identity #
Whiskering a morphism into the algebra and multiplying is the convolution with the identity.
The convolution of the identity with itself is the multiplication.
Convolution with a zero morphism vanishes.
Multiplication by a scalar is a module endomorphism #
Convolution with an even scalar reads the same on either side, once the source is identified with its tensor with the unit.
Multiplication by an even scalar, written on the other side.
Multiplication by an even scalar is a module
endomorphism: it commutes with the multiplication of the algebra
in the second variable. Both sides say g·(a·b) = a·(g·b).
The action of a fixed element is a module map. For any
f : X ⟶ R the convolution gmul f (𝟙 R) absorbs multiplication
by the algebra: a·(f·b) = f·(a·b).
Images as subobjects #
The factorisation of a morphism through its image, read as a morphism into the image subobject.
Equations
Instances For
The factorisation through the image subobject recovers the morphism.
The factorisation through the image subobject is an epimorphism.
Kernel and image are ideals #
The kernel of multiplication by a scalar is an ideal: multiplication by a scalar is a module endomorphism, so anything it kills stays killed after multiplying by the algebra.
The image of a module map is an ideal. If a morphism into the algebra absorbs multiplication by the algebra, its image does too: tensoring preserves the covering epimorphism onto the image.
The image of multiplication by a scalar is an ideal.
Simplicity makes multiplication invertible #
A subobject equal to ⊥ has a zero arrow, so a morphism whose
image it is vanishes.
A morphism whose image subobject is ⊤ is an epimorphism.
Simplicity makes multiplication by a nonzero scalar
invertible. The kernel is an ideal different from ⊤, because a
scalar whose multiplication vanishes is itself zero; the image is an
ideal different from ⊥, for the same reason. So the kernel is ⊥
and the image is ⊤, and a monomorphism which is an epimorphism of
an abelian category is an isomorphism. No hypothesis on the unit is
needed: a nonzero scalar already rules out both bad alternatives.
The even part is a field #
Every nonzero even scalar of a simple algebra is invertible: the preimage of the unit under multiplication by the scalar is its inverse.
The even part of the Γ-algebra of a simple algebra is a field.
The even part of the Γ-algebra of a simple algebra, as a field.
Equations
- RS.gammaEvenField R L hsimple hne = ⋯.toField
Instances For
The odd part vanishes #
The odd part of the Γ-algebra of a simple algebra
vanishes. An odd element f acts on the algebra by
gmul f (𝟙 R), whose image is an ideal, so simplicity leaves two
alternatives and the action vanishes under both: if the image is
⊥ the action is zero outright, and if the image is ⊤ the action
is an epimorphism, which the square-zero law of an odd element
makes annihilate itself. Evaluating the zero action at the unit
returns f.